How far does the object compress the spring
Web2 aug. 2024 · A 1.30 kg object is held 1.20 m above a relaxed, massless vertical spring with a force constant of 310 N/m. The object is dropped onto the spring. (a) How far does the object compress the spring? ________m (b) How far does the object compress the spring if the same experiment is performed on the moon, where g = 1.63 m/s2? … Web12 aug. 2016 · You draw the free body diagram of the object at one end, and it shows a spring force. This force is the push, the spring exerts on the object because it is …
How far does the object compress the spring
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WebIt till the block becomes motionless.The kinetic frictional force is 15 N.The spring constant: 100000 N/m.The spring compresses by Medium View solution > A 1.50−kg object is held 1.20m above a relaxed mass-less, vertical spring with a force constant of 320N/M The object is dropped onto the spring How far does the object compress the spring. Hard WebA 1.40-kg object is held 1.25 m above a relaxed, massless vertical spring with a force constant of 300 N/m. The object is dropped onto the spring. (a) How far does the …
WebA 1.80-kg object is held 1.15 m above a relaxed, massless vertical spring with a force constant of 315 N/m. The object is dropped onto the spring. (a) How far does the object compress the spring? 0.396x Your response is within 10% of the correct value. This may be due to roundoff error, or you could have a mistake in your calculation. Web22 dec. 2024 · The good news it’s a simple law, describing a linear relationship and having the form of a basic straight-line equation. The formula for Hooke’s law specifically relates the change in extension of the spring, x , to the restoring force, F , generated in it: F = −kx F = −kx. The extra term, k , is the spring constant.
WebHow far does the object compress the spring if the same experiment is performed on the Moon, where g 1.63 m/s2 and air resistance is neglected? 24. A 1.50-kg object is held … Web1.70 kg object is dropped onto a vertical spring with a force constant of 305 N/m. The object compresses the spring by 1.40 m. Best Match Video Recommendation: Solved by verified expert We don’t have your requested question, but here is a suggested video that might help. Best Match Question:
Web22 jul. 2024 · The initial gravitational potential energy of the object is: where. m = 1.50 kg is the mass of the object. g = 9.8 m/s^2 is the acceleration of gravity. h = 1.27 m is the height of the object. The final elastic potential energy of the compressed spring is. where. k = 300 N/m is the spring constant. x is the compression of the spring
Web14 sep. 2014 · About Press Copyright Contact us Creators Advertise Developers Terms Privacy Policy & Safety How YouTube works Test new features NFL Sunday Ticket … keynesian economics is focused onWebThe equation that relates the amount of elastic potential energy (PEspring) to the amount of compression or stretch (x) is. PE spring = ½ • k•x 2. where k is the spring constant (in … island 4 audio logs halo infiniteWeb14 sep. 2014 · About Press Copyright Contact us Creators Advertise Developers Terms Privacy Policy & Safety How YouTube works Test new features NFL Sunday Ticket Press Copyright ... island 4 collectibles halo infiniteWebTranscribed Image Text: A 1.60-kg object is held 1.30 m above a relaxed, massless vertical spring with a force constant of 315 N/m. The object is dropped onto the spring. (a) How far does the object compress the spring? (b) Repeat part (a), but this time assume a constant air-resistance force of 0.800 N acts on the object during its motion. m (c) … island 3 tagekeynesian economics is primarily focusedWebHow far is the spring compressed ; A box of mass m = 1.50 kg is dropped from rest onto a massless, vertical spring with spring constant k = 2.35 \times 10^2 N/m that is initially at its natural length. How far is the spring compressed ; A 65-kg object is dropped from rest a distance of 4.3 m onto a spring with a stiffness coefficient of 6.2 x ... keynesian economics liberalismWeb[What happens when a spring is stretched too far?] Equations Hooke’s law The force required to stretch an elastic object such as a metal spring is directly proportional to the … island 4 hours away from st. petersburg fl